document.write( "Question 79690: Sometimes both equations will need to be multiplied to obtain opposite coefficients\r
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document.write( "EXAMPLE
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document.write( "3X + 5Y =6\r
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document.write( "-4X + 2Y =5 \n" );
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Algebra.Com's Answer #57179 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3X + 5Y =6 \n" ); document.write( "-4X + 2Y =5 \n" ); document.write( "------------- \n" ); document.write( "Let's say you want to get rid of the X-terms: \n" ); document.write( "Multiply 1st equation by 4 so you get a 12X term: \n" ); document.write( "Multiply 2nd equation by 3 so you get a -12x term: \n" ); document.write( "---------- \n" ); document.write( "12x + 20y = 24 \n" ); document.write( "-12x+ 6y = 15 \n" ); document.write( "----------- \n" ); document.write( "Now, add the two equations to get: \n" ); document.write( "26y=39 \n" ); document.write( "y=39/26 \n" ); document.write( "----------- \n" ); document.write( "Substitute that value of y into one of the equations so you can solve for x: \n" ); document.write( "3x +5(39/26) = 6 \n" ); document.write( "x+5(13/26) = 2 \n" ); document.write( "x+5/2 = 2 \n" ); document.write( "x= -1/2 \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |