document.write( "Question 938455: How would I use the elimination method to for this equation?
\n" ); document.write( "5r+2t=5
\n" ); document.write( "3r-7t=3
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Algebra.Com's Answer #571723 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\"3r-7t=3\"\r
\n" ); document.write( "\n" ); document.write( "I am going to use this solver which uses variables \"x\" and \"y\", and your variables are \"r\" and \"t\"; so, you just take \"x=r\" and \"y=t\"\r
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"5%2Ax%2B2%2Ay=5\"
\n" ); document.write( " \"3%2Ax-7%2Ay=3\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 5 and 3 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 5 and 3 is 15, we need to multiply both sides of the top equation by 3 and multiply both sides of the bottom equation by -5 like this:
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\n" ); document.write( " \"3%2A%285%2Ax%2B2%2Ay%29=%285%29%2A3\" Multiply the top equation (both sides) by 3
\n" ); document.write( " \"-5%2A%283%2Ax-7%2Ay%29=%283%29%2A-5\" Multiply the bottom equation (both sides) by -5
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"15%2Ax%2B6%2Ay=15\"
\n" ); document.write( " \"-15%2Ax%2B35%2Ay=-15\"
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\n" ); document.write( " Notice how 15 and -15 add to zero (ie \"15%2B-15=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2815%2Ax-15%2Ax%29%2B%286%2Ay%2B35%2Ay%29=15-15\"
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\n" ); document.write( " \"%2815-15%29%2Ax%2B%286%2B35%29y=15-15\"
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\n" ); document.write( " \"cross%2815%2B-15%29%2Ax%2B%286%2B35%29%2Ay=15-15\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"41%2Ay=0\"
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\n" ); document.write( " \"y=0%2F41\" Divide both sides by \"41\" to solve for y
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\n" ); document.write( " \"y=0\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"5%2Ax%2B2%2Ay=5\" to solve for x
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\n" ); document.write( " \"5%2Ax%2B2%280%29=5\" Plug in \"y=0\"
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\n" ); document.write( " \"5%2Ax%2B0=5\" Multiply
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\n" ); document.write( " \"5%2Ax=5-0\" Subtract \"0\" from both sides
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\n" ); document.write( " \"5%2Ax=5\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F5%29%285%29%29%2Ax=%285%29%281%2F5%29\" Multiply both sides by \"1%2F5\". This will cancel out \"5\" on the left side.
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\n" ); document.write( " \"x=1\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=1\", \"y=0\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"1\", \"0\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"5%2Ax%2B2%2Ay=5\"
\n" ); document.write( " \"3%2Ax-7%2Ay=3\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"5%2Ax%2B2%2Ay=5\" (red) \"3%2Ax-7%2Ay=3\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"1\",\"0\"). This verifies our answer.
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