document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=938455>Question 938455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I use the elimination method to for this equation?<BR>\n" );
document.write( "5r+2t=5<BR>\n" );
document.write( "3r-7t=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #571718 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=571718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7(5r+2t = 5)<BR>\n" );
document.write( "<u>2(3r-7t) = 3)</u>  Re TY, it is 35r +  2(3r) = 41r<BR>\n" );
document.write( "...<BR>\n" );
document.write( "35r + 14t = 35<BR>\n" );
document.write( "<u>6r - 14t = 6</u>  <BR>\n" );
document.write( "41r = 41<BR>\n" );
document.write( "41r = 41<BR>\n" );
document.write( "r = 1  and t = 0  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2B2t+=+5 ALIGN=MIDDLE  ALT=\"5%2B2t+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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