document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=938453>Question 938453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I use the elimination method to solve for this equation.\r<BR>\n" );
document.write( "\n" );
document.write( "5r+3t=-1<BR>\n" );
document.write( "-2r-5t=-11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #571711 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=571711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ORIGINAL SYSTEM<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "5r+3t=-1<BR>\n" );
document.write( "-2r-5t=-11<BR>\n" );
document.write( "---------------\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Multiply both members of either or both equations to make the coefficients of either variable become equal in their absolute value.  Read and reread that again thinking carefully.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Try elimination of t.<BR>\n" );
document.write( "5 and 3 are factors to use to do this:<BR>\n" );
document.write( "-<BR>\n" );
document.write( "5(5r+3t)=5(-1)<BR>\n" );
document.write( "25r+15t=-5<BR>\n" );
document.write( "-<BR>\n" );
document.write( "3(-2r-5t)=3(-11)<BR>\n" );
document.write( "-6r-15t=-33<BR>\n" );
document.write( "-<BR>\n" );
document.write( "resulting system<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%2825r%2B15t=-5%2C-6r-15t=-33%29 ALIGN=MIDDLE  ALT=\"system%2825r%2B15t=-5%2C-6r-15t=-33%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "These are two equations.  If you have something like D=F, and then do <BR>\n" );
document.write( "D+k=F+k,  then this equation is equivalent to D=F.<BR>\n" );
document.write( "Also, if you have k=m, then you can do<BR>\n" );
document.write( "D+k=F+m, and this too is equivalent to D=F.<BR>\n" );
document.write( "That would be the use of the substitution operation from a system like <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28D=F%2Ck=m%29 ALIGN=MIDDLE  ALT=\"system%28D=F%2Ck=m%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "You will do the same thing for the \"resulting system\" just found above.<BR>\n" );
document.write( "Sum the lefthand members, sum the right hand members, and set them equal. This will eliminate the terms of t...\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=25r%2B15t%2B%28-6r-15t%29=-5%2B%28-33%29 ALIGN=MIDDLE  ALT=\"25r%2B15t%2B%28-6r-15t%29=-5%2B%28-33%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=19r=-38 ALIGN=MIDDLE  ALT=\"19r=-38\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28r=-2%29 ALIGN=MIDDLE  ALT=\"highlight%28r=-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "You can handle the other variable in nearly a similar way.  <BR>\n" );
document.write( "To eliminate r, starting from the ORIGINAL system, you should choose factors of 2 and 5. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );