document.write( "Question 79676: Can anyone make any sense out of this problem? I don't understand at all the statements about calculus and/or how it would even look or where I would even begin. Any suggestions?\r
\n" ); document.write( "\n" ); document.write( "The perimeter = 2L +2W = 400 or L+W = 200
\n" ); document.write( "The area = LW so if you substitute for L you get (200-W)W = A
\n" ); document.write( "or A = 200W -W^2\r
\n" ); document.write( "\n" ); document.write( "If you're allowed to use calculus, you can show easily that the maximum
\n" ); document.write( "area occurs when W = 100 which, of course, means that L = 100 and you have a square plot.\r
\n" ); document.write( "\n" ); document.write( "If you can't use calculus, you can simply put in a value for W, calculate A, and keep trying until you find the maximum value for A.
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Algebra.Com's Answer #57170 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If you aren't allowed to use calculus, then you can simply graph the function\r
\n" ); document.write( "\n" ); document.write( "\"A=200w-w%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"graph%28+500%2C+500%2C+-100%2C+200%2C+-1000%2C+10000%2C+200x-x%5E2+%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now just use your calculator to find the maximum of the function, which turns out to be at the point\r
\n" ); document.write( "\n" ); document.write( "(100,10000)\r
\n" ); document.write( "\n" ); document.write( "So the maximum area is 10,000 square units where the width is 100 units
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