document.write( "Question 938345: the square root of three times a certain number is subtracted from the number and the result is 6 . find the number
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Algebra.Com's Answer #571644 by ankor@dixie-net.com(22740)\"\" \"About 
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the square root of three times a certain number is subtracted from the number and the result is 6 .
\n" ); document.write( "\"x+-+sqrt%283x%29+=+6\"
\n" ); document.write( "We can arrange it like this
\n" ); document.write( "x - 6 = \"sqrt%283x%29\"
\n" ); document.write( "square both sides
\n" ); document.write( "(x-6)^2 = 3x
\n" ); document.write( "x^2 - 12x + 36 = 3x
\n" ); document.write( "x^2 - 12x - 3x + 36 = 0
\n" ); document.write( "x^2 - 15x + 36 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-12)(x-3) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 12
\n" ); document.write( "x = 3
\n" ); document.write( ":
\n" ); document.write( "Check both solutions in the original equation
\n" ); document.write( "\"12+-+sqrt%283%2A12%29+=+6\"
\n" ); document.write( "12 - 6 = 6, a good solution
\n" ); document.write( "and
\n" ); document.write( "\"3+-+sqrt%283%2A3%29+=+6\"
\n" ); document.write( "3 - 3 does not = 6, no solution
\n" ); document.write( ":
\n" ); document.write( "find the number x = 12 \n" ); document.write( "
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