document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79641>Question 79641</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify the expression.  all variables represent positive real numbers.  Please help me!  thanks!\r<BR>\n" );
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document.write( "square root of:\r<BR>\n" );
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document.write( "80x^9y^11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57160 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 80 BEING AN EVEN NUMBER IS DIVISABLE BY 2 THUS 80/2=40 NOW 40 IS DIVISABLE BY 2 THUS 40/2=20 NEW 20 IS DIVISABLE BY 2 THUS 20/2=10 NOW 10 IS DIVISABLE BY 2 THUS 10/2=5. WE ACN QUIT NOW BECAUSE 5 IS A PRIME NUMBER. SO WE NOW HAVE <BR>\n" );
document.write( "2*2*2*2=16 & THE SQRT16=4.<BR>\n" );
document.write( "THAT TAKES CARE OF THE NUMBER 4SQRT5.<BR>\n" );
document.write( "NOW WE ATTACK THE X^9=X^8*X^1 & SQRTX^8=X^4 SO WE HAVE X^4SQRTX<BR>\n" );
document.write( "NOW FOR THE Y^9 TERM Y^11=Y^10*Y^1 OR SQRT^11=Y^5SQRTY THUS WE HAVE THE FOLLOWING REDUCED SET OF TERMS: <BR>\n" );
document.write( "SQRT[80(Y^9)(Y^11)]=4(X^4)(Y^5)SQRT(5XY) </SPAN>\n" );
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