document.write( "Question 938100: Two vertices of an equilateral triangle are (3,4)and (-2,3) the third vertex can be \n" ); document.write( "
Algebra.Com's Answer #571583 by KMST(5328)\"\" \"About 
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We know one side of the triangle, connecting vertices \"A%283%2C4%29\" and \"B%28-2%2C3%29\" .
\n" ); document.write( "The length of side AB is
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\n" ); document.write( "Side AB is a segment of a line with slope
\n" ); document.write( "\"m=%284-3%29%2F%283-%28-2%29%29=1%2F5\".
\n" ); document.write( "The midpoint of AB, point P, has coordinates
\n" ); document.write( "\"x%5BP%5D=%283%2B%28-2%29%29%2F2=1%2F2\" and \"y%5BP%5D=%284%2B3%29%2F2=7%2F2\" .
\n" ); document.write( "The equilateral triangles with side AB are ABD and ABC,
\n" ); document.write( "with C and D on opposite sides of segment AB.
\n" ); document.write( "Visualizing the location of vertices C and D is easy,
\n" ); document.write( "but I could not think of a simple way to calculate their coordinates.
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\n" ); document.write( "The perpendicular bisector of AB contains the altitude of those triangles.
\n" ); document.write( "That perpendicular bisector is a line perpendicular to AB,
\n" ); document.write( "and passing through point P (the midpoint of AB).
\n" ); document.write( "Being perpendicular to a line with slope \"m=1%2F5\" ,
\n" ); document.write( "that altitude is part of a line with slope \"-1%2Fm=-5\" .
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\n" ); document.write( "\"PA=%281%2F2%29%2AAB=sqrt%2826%29%2F2\" .
\n" ); document.write( "Since angle PAC is a \"60%5Eo\",
\n" ); document.write( "\"tan%28PAC%29=PC%2FPA=sqrt%283%29\"-->\"PC=sqrt%283%29%2APA=sqrt%283%29%2Asqrt%2826%29%2F2=sqrt%2878%29%2F2\"
\n" ); document.write( "So the length of PC and PD is \"PC=PC=sqrt%2878%29%2F2\" ,
\n" ); document.write( "but what are the coordinates of C and D?
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\n" ); document.write( " Since the slope of CD is \"-5\" , \"b=5a\" ,
\n" ); document.write( "and in those two green right triangles
\n" ); document.write( "\"a%5E2%2Bb%5E2=a%5E2%2B%285a%29%5E2=a%5E2%2B25a%5E2=26a%5E2=%28sqrt%2878%29%2F2%29%5E2=78%2F4\"--->\"a%5E2=78%2F4%2A26=3%2F4\"--->\"a=sqrt%283%29%2F2\"--->\"b=5sqrt%283%29%2F2\"
\n" ); document.write( "Then,
\n" ); document.write( "\"x%5BC%5D=1%2F2%2Bsqrt%283%29%2F2=%281%2Bsqrt%283%29%29%2F2=about1.37\" (rounded),
\n" ); document.write( "\"y%5BC%5D=7%2F2-5sqrt%283%29%2F2=%287-5sqrt%283%29%29%2F2=about-0.83\" (rounded),
\n" ); document.write( "\"x%5BD%5D=1%2F2-sqrt%283%29%2F2=%281-sqrt%283%29%29%2F2=about-0.37\" (rounded), and
\n" ); document.write( "\"y%5BD%5D=7%2F2%2B5sqrt%283%29%2F2=%287%2B5sqrt%283%29%29%2F2=about7.83\" (rounded).
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