document.write( "Question 938036: In how many different ways can a panel of 12 jurors and 2 alternates be chosen from a group of 20 prospective jurors? \n" ); document.write( "

Algebra.Com's Answer #571568 by KMST(5328) $\"\"$ $\"About$

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The way I see it, choosing the $\"12%2B2=14\"$ people who could form the final panel is the same as choosing the $\"20-14=6\"$ people that are not wanted.
\n" ); document.write( "That is $\"20%2A19%2A18%2A17%2A16%2A15%2F%281%2A2%2A3%2A4%2A5%2A6%29=19%2A17%2A15%2A8=38760\"$ ,
\n" ); document.write( "so there are $\"38760\"$ different sets of $\"14\"$ people that can be picked.
\n" ); document.write( "For each of those $\"14\"$ sets, there are
\n" ); document.write( " $\"14%2A13%2F%281%2A2%29=7%2A13=91\"$ possible sets of $\"2\"$ alternates.
\n" ); document.write( "That gives us $\"38760%2A91=highlight%283527160%29\"$ possible panels that can be formed.
\n" ); document.write( "
\n" ); document.write( "Another way:
\n" ); document.write( "Out of the $\"20\"$ people available, there are
\n" ); document.write( " $\"20%21%2F%288%2112%21%29=125970\"$ ways to chose the $\"12\"$ jurors,
\n" ); document.write( "and in each case, from the $\"20-12=8\"$ people remaining, there are
\n" ); document.write( " $\"8%2A7%2F%281%2A2%29=4%2A7=28\"$ ways to choose two alternates.
\n" ); document.write( "So, there are $\"125970%2A28=highlight%283527160%29\"$ possible panels that can be formed. \n" ); document.write( "

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