document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=938153>Question 938153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many terms has a G.P whose second term is 1/2 and the common ratio and the last term are 1/2 and 1/120 respectively </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #571508 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=571508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many terms has a G.P whose second term is 1/2 and the common ratio and the last term are 1/2 and 1/120 respectively<BR>\n" );
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document.write( "a(2) = ar = 1/2<BR>\n" );
document.write( "Since r = 1/2, a = 1<BR>\n" );
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document.write( "Last term = a(n) = ar^(n-1) = 1*(1/2)^(n-1) = 1/120<BR>\n" );
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document.write( "Solve:: (1/2)^(n-1) = 1/120<BR>\n" );
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document.write( "(n-1)log(1/2) = log(1/120)<BR>\n" );
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document.write( "n-1 = log(1/120)/log(1/2) = 6.90<BR>\n" );
document.write( "n = 7.90<BR>\n" );
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document.write( "Comment:: That answer has to be a whole number.<BR>\n" );
document.write( "Did you post the problem correctly?<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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