document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=938121>Question 938121</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boat can travel 20 km per hour. the current in the river flows at 5 km per hour. so downstream the boat travels 25km per hour and upstream 15km per hour . the boat has fuel to last for 3 hours . the boat leaves its base and travels downstream. at what time the boat must turn around to get back to base without running out of fuel?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #571457 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=571457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D%2F%2825mph%29+%2B+D%2F%2815mph%29+=+3hr ALIGN=MIDDLE  ALT=\"D%2F%2825mph%29+%2B+D%2F%2815mph%29+=+3hr\"   DISABLED_style= \"max-width:90%; height:auto;\" > |Multiplying thru by 75 so as all denominators = 1<BR>\n" );
document.write( "3d + 5D = 225<BR>\n" );
document.write( "8D = 225<BR>\n" );
document.write( "D = 28.125k<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=28.125%2F%2825kph%29 ALIGN=MIDDLE  ALT=\"28.125%2F%2825kph%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1.125hr boat must turn around <BR>\n" );
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