document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79618>Question 79618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve 2/3(6x+30)=x + 5(x+4)-2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57142 by </B><A HREF=/tutors/aboutme.mpl?userid=doctor_who><B>doctor_who(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=doctor_who><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/3(6x+30)=x + 5(x+4)-2x\r<BR>\n" );
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document.write( "Expand the left hand side of the equation first.  This is easy since two thirds of six is four and two thirds of thirty is twenty.\r<BR>\n" );
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document.write( "4x + 20 = x + 5(x+4) - 2x\r<BR>\n" );
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document.write( "Expand the right hand side :\r<BR>\n" );
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document.write( "4x + 20 = x + 5x + 20 -2x\r<BR>\n" );
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document.write( "Collect up all the x terms on the right hand side :\r<BR>\n" );
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document.write( "4x + 20 = x + 5x - 2x + 20\r<BR>\n" );
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document.write( "So the total number of \"x\"'s on the right hand side is 1 + 5 -2 = 4\r<BR>\n" );
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document.write( "4x + 20 = 4x + 20\r<BR>\n" );
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document.write( "Hey !  Look at that ! You've got the same thing on both sides of the equation !\r<BR>\n" );
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document.write( "This means that it doesn't matter what value x is, the equation works for ALL values of x.  (ANSWER) </SPAN>\n" );
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