document.write( "Question 938062: A car leaves A at 8 AM and travels to B at a rate of 60 kph. A bus leaves B at 8:30 AM and travels to A at a rate of 75 kph. If the car and the bus pass each other midway between A and B, at what time will the car pass the bus?\r
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\n" ); document.write( "\n" ); document.write( "As much as I like to put my own solution .. I can't because I really don't how and I need this as review for a competition so pleaae help me? \n" ); document.write( "
Algebra.Com's Answer #571392 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A car leaves A at 8 AM and travels to B at a rate of 60 kph.
\n" ); document.write( " A bus leaves B at 8:30 AM and travels to A at a rate of 75 kph.
\n" ); document.write( " If the car and the bus pass each other midway between A and B, at what time will the car pass the bus?
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\n" ); document.write( "If the meet half-way, the will both have traveled the same distance
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\n" ); document.write( "let t = bus travel time (till when they meet)
\n" ); document.write( "then
\n" ); document.write( "(t+.5) = car travel time. (left a half hour earlier)
\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( "75t = 60(t+.5)
\n" ); document.write( "75t = 60s + 30
\n" ); document.write( "75t - 60t = 30
\n" ); document.write( "15t = 30
\n" ); document.write( "t = 30/15
\n" ); document.write( "t = 2 hrs, is the bus travel time
\n" ); document.write( "8:30 + 2:00 = 10:30 meeting time
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\n" ); document.write( "Car travel time = 2.5 hrs, 8:00 + 2.5 = 10:30 also
\n" ); document.write( "Check the distance for each, should be the same
\n" ); document.write( "2*75 = 150 mi
\n" ); document.write( "2.5*60 = 150 mi \n" ); document.write( "
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