document.write( "Question 938021: a man can row 15 km downstream in 1 hour and upstream for the same distance in 3 hours.Using the same speed,how far can the man row in 3 hours in still water? \n" ); document.write( "
Algebra.Com's Answer #571371 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
a man can row 15 km downstream in 1 hour and upstream for the same distance in 3 hours.Using the same speed,how far can the man row in 3 hours in still water?
\n" ); document.write( "let x=speed of rowboat in still water
\n" ); document.write( "let c=speed of current
\n" ); document.write( "x+c=speed of rowboat downstream
\n" ); document.write( "x-c=speed of rowboat upstream
\n" ); document.write( "travel time*speed=distance
\n" ); document.write( "..
\n" ); document.write( "3(x-c)=15
\n" ); document.write( "1(x+c)=15
\n" ); document.write( "..
\n" ); document.write( "3x-3c=15
\n" ); document.write( "x+c=15
\n" ); document.write( "..
\n" ); document.write( "3x-3c=15
\n" ); document.write( "3x+3c=45 (mult. eq. by 3)
\n" ); document.write( "add
\n" ); document.write( "6x=60
\n" ); document.write( "x=10 km/h=speed of rowboat in still water
\n" ); document.write( "how far can the man row in 3 hours in still water? 30 km
\n" ); document.write( "
\n" ); document.write( "
\n" );