document.write( "Question 938021: a man can row 15 km downstream in 1 hour and upstream for the same distance in 3 hours.Using the same speed,how far can the man row in 3 hours in still water? \n" ); document.write( "
Algebra.Com's Answer #571371 by lwsshak3(11628) ![]() You can put this solution on YOUR website! a man can row 15 km downstream in 1 hour and upstream for the same distance in 3 hours.Using the same speed,how far can the man row in 3 hours in still water? \n" ); document.write( "let x=speed of rowboat in still water \n" ); document.write( "let c=speed of current \n" ); document.write( "x+c=speed of rowboat downstream \n" ); document.write( "x-c=speed of rowboat upstream \n" ); document.write( "travel time*speed=distance \n" ); document.write( ".. \n" ); document.write( "3(x-c)=15 \n" ); document.write( "1(x+c)=15 \n" ); document.write( ".. \n" ); document.write( "3x-3c=15 \n" ); document.write( "x+c=15 \n" ); document.write( ".. \n" ); document.write( "3x-3c=15 \n" ); document.write( "3x+3c=45 (mult. eq. by 3) \n" ); document.write( "add \n" ); document.write( "6x=60 \n" ); document.write( "x=10 km/h=speed of rowboat in still water \n" ); document.write( "how far can the man row in 3 hours in still water? 30 km \n" ); document.write( " \n" ); document.write( " |