document.write( "Question 937992: In an alloy of 100 pounds of zinc and copper there are 75 pounds of copper. How much copper must be added so that the alloy may be 10% zinc ?
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document.write( "Can you please give an equation and detailed explanation \n" );
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Algebra.Com's Answer #571351 by mananth(16946)![]() ![]() You can put this solution on YOUR website! The alloy contains 75 lbs copper in 100 lbs of alloy = 75% \n" ); document.write( "So remaining is Zinc = 25 %\r \n" ); document.write( "\n" ); document.write( "You need to reduce the zinc % to 10% by adding copper which contains no zinc\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--- percent ---------------- Amount \n" ); document.write( "Zinc in Alloy 25 ---------------- 100 lbs \n" ); document.write( "copper 0 ---------------- x lbs \n" ); document.write( "Mixture 10 ---------------- 100 + x lbs \n" ); document.write( " \n" ); document.write( "25 * 100 + 0 x = 10 ( 100 + x ) \n" ); document.write( "2500 + 0 x = 1000 + 10 x \n" ); document.write( "0 x -10 x = -2500 + 1000 \n" ); document.write( "-10 x = -1500 \n" ); document.write( "/ -10 \n" ); document.write( "x = 150 lbs copper \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |