document.write( "Question 937920: A 150 minute river cruise goes 14km upstream and then back again. The river has a current of 3km an hour going downstream. What is the boat's speed in still water and how long was the upstream journey in minutes? \n" ); document.write( "
Algebra.Com's Answer #571346 by mananth(16946)\"\" \"About 
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boat speed x km Time forward + time return = hours
\n" ); document.write( "current speed 3 km
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\n" ); document.write( "against current x- 3 km/h
\n" ); document.write( "with current x+ 3 km/h
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\n" ); document.write( "Distance= 14 km
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\n" ); document.write( "Time against + time with = 2.5 hours
\n" ); document.write( "t=d/r
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\n" ); document.write( "14 /( x + 3 ) + 14
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\n" ); document.write( "LCD = (x - 3 ) ( x +
\n" ); document.write( "14 *( x - 3 ) + 14
\n" ); document.write( "14 x - -42 + 14 x +
\n" ); document.write( "28 x = 2.5 x ^2 -22.5
\n" ); document.write( "2.5 x ^2 - -28 x - -22.5 =
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\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 2.5 , b= -28 , c= -22.5
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\n" ); document.write( "b^2-4ac= 784 + 225
\n" ); document.write( "b^2-4ac= 1009
\n" ); document.write( "\"%09sqrt%28%091009%09%29=%0931.76%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 28 + 31.76 )/ 5
\n" ); document.write( "x1= 11.95
\n" ); document.write( "\"x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x2=( 28 -31.76 ) / 5
\n" ); document.write( "x2= -0.75
\n" ); document.write( "Ignore negative value
\n" ); document.write( "boat speed 11.953 km/h \r
\n" ); document.write( "\n" ); document.write( "Time upstream = (14/8.953)*60 =94 minutes
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\n" ); document.write( "m.ananth@hotmail.ca
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