document.write( "Question 937985: hey there,\r
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document.write( "I'm doing some basic trig functions and would like to get some insight into this question i am struggling with.\r
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document.write( "let 0 <= delta < pi/2 \r
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document.write( "(a) working from the unit circle, demonstrate that tan(pi - delta) = -tan delta
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document.write( "(b) hence, find the exact value of tan(pi - pi/6)\r
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document.write( "thanks, \n" );
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Algebra.Com's Answer #571335 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! let 0 <= delta < pi/2 \n" ); document.write( "(a) working from the unit circle, demonstrate that tan(pi - delta) = -tan delta \n" ); document.write( "Draw a unit circle centered at (0,0) \n" ); document.write( "Pick a point in QII ; Label the point (-x,y) \n" ); document.write( "x is negative and y is positive \n" ); document.write( "------------ \n" ); document.write( "That point is at pi-delta, eg. 180-30 = 150 degrees \n" ); document.write( "tan(pi-delta) = y/-x = -y/x \n" ); document.write( "----------- \n" ); document.write( "------ \n" ); document.write( "Draw a diameter from that point, thru (0,0) till it meets the circle in QIV \n" ); document.write( "That point has coordinates (x,-y) \n" ); document.write( "That point is delta below the x-ax or at -delta \n" ); document.write( "The tangent is -y/x which is the negative of tan(pi-delta) \n" ); document.write( "------------------------------------- \n" ); document.write( "(b) hence, find the exact value of tan(pi - pi/6) = -tan(pi/6) = -1/sqrt(3) \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------- \n" ); document.write( " \n" ); document.write( " |