document.write( "Question 937918: Find three consecutive positive odd integers such that the product of the first two is eight more than five times the third. \n" ); document.write( "
Algebra.Com's Answer #571333 by ankor@dixie-net.com(22740)\"\" \"About 
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Find three consecutive positive odd integers
\n" ); document.write( "x, (x+2), (x+4)
\n" ); document.write( " such that the product of the first two is eight more than five times the third.
\n" ); document.write( "x(x+2) = 5(x+4) + 8
\n" ); document.write( "x^2 + 2x = 5x + 20 + 8
\n" ); document.write( "combine like terms on the left to form a quadratic equation
\n" ); document.write( "x^2 + 2x - 5x - 28 = 0
\n" ); document.write( "x^2 - 3x - 28 = 0
\n" ); document.write( "Factor to
\n" ); document.write( "(x-7)(x+4) = 0
\n" ); document.write( "the positive solution is what they want here
\n" ); document.write( "x = 7, 9, 11 are the three integers
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\n" ); document.write( "See if that works out in the statement:
\n" ); document.write( "\"the product of the first two is eight more than five times the third.\"
\n" ); document.write( "7(9) = 5(11) + 8
\n" ); document.write( "63 = 55 + 8
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