document.write( "Question 937969: Malik canoed against the current for 2 hours and then with the current for 1 hour. Julio traveled against the current for 2.5 hours and with the current for 1.5 hours. If they traveled a total of 9.5 miles against the current and 20.5 miles with the current and the current is going 3 miles per hour how fast do Malik and Julio travel in still water? \n" ); document.write( "
Algebra.Com's Answer #571323 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Malik canoed against the current for 2 hours and then with the current for 1 hour. Julio traveled against the current for 2.5 hours and with the current for 1.5 hours. If they traveled a total of 9.5 miles against the current and 20.5 miles with the current and the current is going 3 miles per hour how fast do Malik and Julio travel in still water?\r
\n" ); document.write( "\n" ); document.write( "Let Malik's rate be x mph
\n" ); document.write( "and Julio's rate be y mph\r
\n" ); document.write( "\n" ); document.write( "rate of current = 2 mph\r
\n" ); document.write( "\n" ); document.write( "Malik upstream distance = (x-3)*2
\n" ); document.write( "Jukio's upstream distance = (y-3)*2.5 \r
\n" ); document.write( "\n" ); document.write( "2(x-3)+2.5(y-3)= 9.5
\n" ); document.write( "2x-6+2.5y-7.5= 9.5
\n" ); document.write( "2x+2.5y -13.5=9.5
\n" ); document.write( "2x+2.5y=23
\n" ); document.write( "multiply by 2
\n" ); document.write( "4x+5y=46................(1)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Similarly
\n" ); document.write( "down stream\r
\n" ); document.write( "\n" ); document.write( "1(x+3)+1.5(y+3)=20.5\r
\n" ); document.write( "\n" ); document.write( "x+3 +1.5y+4.5 =20.5\r
\n" ); document.write( "\n" ); document.write( "x+1.5y=13
\n" ); document.write( "multiply by -4
\n" ); document.write( "-4x-6y=--54...........(2)\r
\n" ); document.write( "\n" ); document.write( "Add (1) & (2)
\n" ); document.write( "-y= -8
\n" ); document.write( "y= 8\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "4x+5y=46\r
\n" ); document.write( "\n" ); document.write( "plug y\r
\n" ); document.write( "\n" ); document.write( "we get 4x+40=46
\n" ); document.write( "x=1.5\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );