document.write( "Question 937803: five times the square root of 1 less than a number is equal to 3 more than te number . find the number.
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Algebra.Com's Answer #571234 by ankor@dixie-net.com(22740)\"\" \"About 
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five times the square root of 1 less than a number is equal to 3 more than the number .
\n" ); document.write( " find the number.
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\n" ); document.write( "Write an equation for exctly for what it says
\n" ); document.write( "\"5%2Asqrt%28x-1%29+=+x+%2B+3\"
\n" ); document.write( "square both sides
\n" ); document.write( "25(x-1) = (x + 3)^2
\n" ); document.write( "FOIL (x+3)(x+3)
\n" ); document.write( "25x - 25 = x^2 + 6x + 9
\n" ); document.write( "Combine like terms on the right
\n" ); document.write( "0 = x^2 + 6x - 25x + 9 + 25
\n" ); document.write( "0 = x^2 - 19x + 34
\n" ); document.write( "Factors to
\n" ); document.write( "(x-17)(x-2) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 17
\n" ); document.write( "and
\n" ); document.write( "x = 2
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\n" ); document.write( "We must check both solutions in the original equation
\n" ); document.write( "\"5%2Asqrt%2817-1%29+=+17+%2B+3\"
\n" ); document.write( "\"5%2Asqrt%2816%29+=+20\"
\n" ); document.write( "5*4 = 20; a good solution
\n" ); document.write( "and
\n" ); document.write( "\"5%2Asqrt%282-1%29+=+2+%2B+3\"
\n" ); document.write( "\"5%2Asqrt%281%29+=+5\"
\n" ); document.write( "5 * 1 = 5; also a good solution
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