document.write( "Question 937803: five times the square root of 1 less than a number is equal to 3 more than te number . find the number.
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Algebra.Com's Answer #571234 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! five times the square root of 1 less than a number is equal to 3 more than the number . \n" ); document.write( " find the number. \n" ); document.write( ": \n" ); document.write( "Write an equation for exctly for what it says \n" ); document.write( " \n" ); document.write( "square both sides \n" ); document.write( "25(x-1) = (x + 3)^2 \n" ); document.write( "FOIL (x+3)(x+3) \n" ); document.write( "25x - 25 = x^2 + 6x + 9 \n" ); document.write( "Combine like terms on the right \n" ); document.write( "0 = x^2 + 6x - 25x + 9 + 25 \n" ); document.write( "0 = x^2 - 19x + 34 \n" ); document.write( "Factors to \n" ); document.write( "(x-17)(x-2) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "x = 17 \n" ); document.write( "and \n" ); document.write( "x = 2 \n" ); document.write( ": \n" ); document.write( "We must check both solutions in the original equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "5*4 = 20; a good solution \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "5 * 1 = 5; also a good solution \n" ); document.write( " |