document.write( "Question 937811: In a pair of consecutive even integers, five times the smaller is less than four times the greater. Find the largest pair of integers satisfying the given condition. \n" ); document.write( "
Algebra.Com's Answer #571214 by Theo(13342)![]() ![]() You can put this solution on YOUR website! let x be the smaller consecutive even integer. \n" ); document.write( "then x + 2 is the larger consecutive even integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x < 4(x+2) becomes 5x < 4x + 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 4x from both sides to get x < 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can check it out with numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's my check with numbers from -20 to 20/\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x is smaller than 8, 5x is smaller than 4(x+2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x is equal to or greater than 8, 5x is not smaller than 4(x+2).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |