document.write( "Question 10771: Solve for t: 2t+7 is less than t+15 and 5t+6 is greater than or equal to 2t+12
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document.write( "please help me i really don't understand how to do this. thanks so much. \n" );
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Algebra.Com's Answer #5712 by askmemath(368)![]() ![]() ![]() You can put this solution on YOUR website! 2t+7 is less than t+15\r \n" ); document.write( "\n" ); document.write( "Subtracting t from both sides \n" ); document.write( "2t+7-t is less than t+15 - t \n" ); document.write( "t+7 is less than 15 \n" ); document.write( "Subtracting fm 7 from both sides \n" ); document.write( "t+7-7 is less than 15-7 \n" ); document.write( "t is less than 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Can you do it for this one?? Follow the same idea as above.Bring the terms containing t to one side and take the rest of the terms to the other side. \n" ); document.write( " 5t+6 is greater than or equal to 2t+12 \n" ); document.write( " |