document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79579>Question 79579</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to solve algebraically, then graph.  Should I solve by elimination or substitution?  Either way I'm running into a lot of mumbo jumbo.  Your help and/or hints are greatly appreciated!<BR>\n" );
document.write( "X^2 - 4Y^2 = 16<BR>\n" );
document.write( "2Y - X = 2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57117 by </B><A HREF=/tutors/aboutme.mpl?userid=elektrisitee><B>elektrisitee(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elektrisitee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use substitution making it x^2=4y^2+16<BR>\n" );
document.write( "then you take the sqare root of the right side<BR>\n" );
document.write( "so that x=2y+4\r<BR>\n" );
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document.write( "then, you plug x into the other equation.\r<BR>\n" );
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