document.write( "Question 937747: A tank can be filled by two taps A and B in 33 and 1/3 minutes (33 minutes and 20 seconds) when they are running together. Tap A running by itself fills the tank in 15 minutes less than tap B. Find the time taken for each tap running by itself to fill the tank. \n" ); document.write( "
Algebra.Com's Answer #571164 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A tank can be filled by two taps A and B in 33 and 1/3 minutes (33 minutes and 20 seconds) when they are running together. Tap A running by itself fills the tank in 15 minutes less than tap B. Find the time taken for each tap running by itself to fill the tank. \n" ); document.write( "--------- \n" ); document.write( "Together DATA: time = 100/3 min/job ; rate = 3/100 job/min \n" ); document.write( "--------------- \n" ); document.write( "Tap A DATA: time = x-15 min/job ; rate = 1/(x-15) job/min \n" ); document.write( "----- \n" ); document.write( "Tap B DATA: time = x min/job ; rate = 1/x job/min \n" ); document.write( "------------------------- \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "------- \n" ); document.write( "1/x + 1/(x-15) = 3/100 \n" ); document.write( "------ \n" ); document.write( "100(x-15)+100x = 3x(x-15) \n" ); document.write( "200x - 1500 = 3x^2 - 45x \n" ); document.write( "----- \n" ); document.write( "3x^2 -245x + 1500 = 0 \n" ); document.write( "Positive solution:: \n" ); document.write( "x = 75 minutes (time for Tap B to do the job) \n" ); document.write( "x-15 = 60 min (time for Tap A to do the job) \n" ); document.write( "--------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |