document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=937378>Question 937378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A student has 100 coins totaling 5.00 dollars. He had no nickels. What coins did he have if 60% were the same type? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #571139 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=571139\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> look at this problem which is similar but leaves out the  60%<BR>\n" );
document.write( "http://www.algebra.com/algebra/homework/word/coins/Word_Problems_With_Coins.faq.question.348068.html\r<BR>\n" );
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document.write( "01p+10d+25q+50h=500<BR>\n" );
document.write( "We have to use a trial and error<BR>\n" );
document.write( "60 per cent are dimes<BR>\n" );
document.write( ".6*100=60*10=600<BR>\n" );
document.write( "makes $6 dollars too much\r<BR>\n" );
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document.write( ".6*100=60*05=300 but there are no nickels\r<BR>\n" );
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document.write( ".6*100=60*01=60 pennies<BR>\n" );
document.write( "60 pennies\r<BR>\n" );
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document.write( "now we need $4.40 using dimes and quarters and halves \r<BR>\n" );
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document.write( "we now need 40 coins which total $4.40<BR>\n" );
document.write( "assuming we are only dealing with two types <BR>\n" );
document.write( "which of these has integer solutions<BR>\n" );
document.write( "x+y=40,<BR>\n" );
document.write( "25x+10y=440<BR>\n" );
document.write( "quarters and dimes\r<BR>\n" );
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document.write( "x+y=40<BR>\n" );
document.write( "25x+50y=440<BR>\n" );
document.write( "quarters and halves<BR>\n" );
document.write( "couldn't add up to 4.40\r<BR>\n" );
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document.write( "x+y=40<BR>\n" );
document.write( "10x+50y=440<BR>\n" );
document.write( "dimes and halves<BR>\n" );
document.write( "this has a solution of y =1 and x=39\r<BR>\n" );
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document.write( "another way<BR>\n" );
document.write( "now are we using dimes quarters or halves<BR>\n" );
document.write( "lets try one half which would leave 390 which would work out with 39 dimes<BR>\n" );
document.write( "so the answer is <BR>\n" );
document.write( "one half <BR>\n" );
document.write( "39 dimes<BR>\n" );
document.write( "60 pennies </SPAN>\n" );
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