document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=937646>Question 937646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the side of a square increase by 4cm.the area increasd by 60sqcm.the sidesquare ios ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #571056 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=571056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the side of a square increase by 4 cm .the area increased by 60 sqcm. the side square are ?<BR>\n" );
document.write( "solution<BR>\n" );
document.write( "Let side of square is X  area will be X^2<BR>\n" );
document.write( "if side increased to 4 cm than new side is X+4  new area =(X+4)^2<BR>\n" );
document.write( "increased area = X^2-(X+4)^2 =60     by using a^2 -b^2= (a+b)(a-b)<BR>\n" );
document.write( "(x-x-4)(x+x+4)=60<BR>\n" );
document.write( "4(2x+4)=60<BR>\n" );
document.write( "2x+4 =15<BR>\n" );
document.write( "2x=15-4=11<BR>\n" );
document.write( "x=11/2=5.5 cm<BR>\n" );
document.write( "answer side of square is 5.5<BR>\n" );
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