document.write( "Question 937638: amber and Matteo are travelling separately from their home Calgary to a wedding 400km away. amber leaves 1h earlier than matteo, but matteo drives at and average 20km/h faster than amber. If they arrive at the wedding at the exact same time what was their average speed at which each of them traveled?
\n" ); document.write( " a)let x represent the time it takes amber to travel to the wedding, write an expression for the average speed that each person travels.
\n" ); document.write( "B) write and solve an equation that represents the difference in their average speeds
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Algebra.Com's Answer #571052 by stanbon(75887)\"\" \"About 
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Amber and Matteo are travelling separately from their home Calgary to a wedding 400km away. Amber leaves 1h earlier than matteo, but matteo drives at and average 20km/h faster than amber. If they arrive at the wedding at the exact same time what was their average speed at which each of them traveled?
\n" ); document.write( " a)let x represent the time it takes amber to travel to the wedding, write an expression for the average speed that each person travels.
\n" ); document.write( "Amber DATA:
\n" ); document.write( "dist = 400 km ; time = x hrs ; rate = 400/x kph
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\n" ); document.write( "Matteo DATA:
\n" ); document.write( "dist = 400 km ; time = x-1 hrs ; rate = 400/(x-1) kph
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\n" ); document.write( " B) write and solve an equation that represents the difference in their average speeds
\n" ); document.write( "Mrate - Arate = 20 kph
\n" ); document.write( "400/(x-1) - 400/x = 20 kph
\n" ); document.write( "------
\n" ); document.write( "400x - 400(x-1) = 20x(x-1)
\n" ); document.write( "400 = 20x(x-1)
\n" ); document.write( "20 = x(x-1)
\n" ); document.write( "x^2-x-20 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "(x-5)(x+4) = 0
\n" ); document.write( "Positive solution::
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\n" ); document.write( "x = 5 hrs (time for Amber)
\n" ); document.write( "x-1 = 4 hrs (time for Matteo)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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