document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10833>Question 10833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me with this problem?  I've tried working it myself and I'm not coming up with the answer the back of my book shows:\r<BR>\n" );
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document.write( "5x-1 over 3 < 2x+1 over 6\r<BR>\n" );
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document.write( "The answer in the back of my book shows  x<3/8 (x is less than three eighths)<BR>\n" );
document.write( "How do they come up with this answer?  Any guidance is greatly appreciated.  Thank you in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5710 by </B><A HREF=/tutors/aboutme.mpl?userid=mike+toye><B>mike toye(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mike+toye><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (5x-1)/3 < (2x +1)/6<BR>\n" );
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document.write( "using the l.c.m. to multiply both sides of the inequality,\r<BR>\n" );
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document.write( " 6X(5x-1)/3 < 6X(2X+1)/6\r<BR>\n" );
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document.write( "simplifying,\r<BR>\n" );
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document.write( "10x-2  <  2x+1\r<BR>\n" );
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document.write( "10x-2x <  1+2<BR>\n" );
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document.write( "    8x <  3<BR>\n" );
document.write( "dividing by coefficient of x,\r<BR>\n" );
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document.write( "     x <  3/8 ans.\r<BR>\n" );
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document.write( "   </SPAN>\n" );
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