document.write( "Question 79558This question is from textbook College Algebra Graphs and Models
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document.write( ": I am trying to figure out this question. ln(x+1)= ln(3x+1)-ln x??? I keep getting x= square root 2x+1. but I don't think that is write??? I am horrible at these. Please help!!! \n" );
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Algebra.Com's Answer #57098 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! ln(x+1)= ln(3x+1)-ln x \n" ); document.write( "ln(x+1) = ln[(3x+1)/x] \n" ); document.write( "Since the ln's are equal, the anti-ln's are equal: \n" ); document.write( "x+1 = (3x+1)/x \n" ); document.write( "x^2+x = 3x+1 \n" ); document.write( "x^2-2x-1=0 \n" ); document.write( "x=[2+-sqrt4-4*-1]/2 \n" ); document.write( "x=[2+-sqrt(8)]/2 \n" ); document.write( "x=[1+-sqrt2] \n" ); document.write( "Positive answer: \n" ); document.write( "x=1+sqrt2 \n" ); document.write( "x=2.1414.... \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |