document.write( "Question 79558This question is from textbook College Algebra Graphs and Models
\n" ); document.write( ": I am trying to figure out this question. ln(x+1)= ln(3x+1)-ln x??? I keep getting x= square root 2x+1. but I don't think that is write??? I am horrible at these. Please help!!! \n" ); document.write( "
Algebra.Com's Answer #57098 by stanbon(75887)\"\" \"About 
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ln(x+1)= ln(3x+1)-ln x
\n" ); document.write( "ln(x+1) = ln[(3x+1)/x]
\n" ); document.write( "Since the ln's are equal, the anti-ln's are equal:
\n" ); document.write( "x+1 = (3x+1)/x
\n" ); document.write( "x^2+x = 3x+1
\n" ); document.write( "x^2-2x-1=0
\n" ); document.write( "x=[2+-sqrt4-4*-1]/2
\n" ); document.write( "x=[2+-sqrt(8)]/2
\n" ); document.write( "x=[1+-sqrt2]
\n" ); document.write( "Positive answer:
\n" ); document.write( "x=1+sqrt2
\n" ); document.write( "x=2.1414....
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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