document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79515>Question 79515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The amount A in an account after t years from an initial principle P invested at an annual rate r compounded continuously is given by A=Pe^r^t where r is expressed as a decimal. How many years will it take an initial investment of $1,000 to grow to $1,700 at the rate of 4.42% compounded continuously? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57095 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The amount A in an account after t years from an initial principle P invested at an annual rate r compounded continuously is given by A=Pe^r^t where r is expressed as a decimal. How many years will it take an initial investment of $1,000 to grow to $1,700 at the rate of 4.42% compounded continuously?<BR>\n" );
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document.write( "A=Pe^rt<BR>\n" );
document.write( "1700 = 1000e^(0.0442t)<BR>\n" );
document.write( "1.7 = e^(0.0442t)<BR>\n" );
document.write( "Take the natural log to get:<BR>\n" );
document.write( "0.0442t= ln(1.7)<BR>\n" );
document.write( "t = 12.0052<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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