document.write( "Question 937541: Find the exact solutions of the given equation in the interval [0,2pi).
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document.write( "cos2x+3cosx+2=0\r
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document.write( "a)x=2pi/3,pi,4pi/3
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document.write( "b)x=0,pi/3,2pi/3,pi,4pi/3
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document.write( "c)x=pi/2,7pi/6,11pi/6
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document.write( "d)x=0
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document.write( "e)x=0,pi/3,pi,5pi/3 \n" );
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Algebra.Com's Answer #570936 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! cos2x+3cosx+2=0 \n" ); document.write( "2cos^2x - 1 + 3cosx + 2 = 0\r \n" ); document.write( "\n" ); document.write( "2cos^2x + 3cosx + 1 = 0 \n" ); document.write( "(2cosx + 1)(cosx + 1) = 0 \n" ); document.write( "cosx = -1/2 0r cosx = -1 \n" ); document.write( ".... \n" ); document.write( "a)x=2pi/3 ,pi, 4pi/3 \n" ); document.write( "........\r \n" ); document.write( "\n" ); document.write( "(cosx, sinx) Summary Unit Circle \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " |