document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=937329>Question 937329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"One triangle has sides 13, 13, and 10. Another triangle has sides 12, 20, and 16. Find the ratio of the smaller area to the larger area. Write your answer using : to indicate ratio.\" <BR>\n" );
document.write( " I found the area of the smaller triangle to be 60 square units by dividing it in half since it is isosceles and obtaining the altitude that way. then i did <BR>\n" );
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document.write( "5(5) +x(x) =13(13)  \r<BR>\n" );
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document.write( "25+x(x) =169\r<BR>\n" );
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document.write( "x(x) =144\r<BR>\n" );
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document.write( "x=12\r<BR>\n" );
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document.write( "10(12)/2 = 6o units squared\r<BR>\n" );
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document.write( "But i am having difficulties fiding the altitude and area of the larger triangle. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #570929 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=570929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area of the smaller<BR>\n" );
document.write( " 5(5) +x(x) =13(13) <BR>\n" );
document.write( " 25+x(x) =169 <BR>\n" );
document.write( " x(x) =144 <BR>\n" );
document.write( " x=12 <BR>\n" );
document.write( " 10(12)/2 = 6o units squared   Good Work.<BR>\n" );
document.write( ".......<BR>\n" );
document.write( "Use Heron's Equation to find the area of a triangle when 3 sides are given <BR>\n" );
document.write( "sides 12, 20, and 16.<BR>\n" );
document.write( "A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29 ALIGN=MIDDLE  ALT=\"sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  s = 1/2P = 24<BR>\n" );
document.write( "A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2824%2812%29%284%29%288%29%29 ALIGN=MIDDLE  ALT=\"sqrt%2824%2812%29%284%29%288%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 96<BR>\n" );
document.write( ".....<BR>\n" );
document.write( "ratio of the smaller area to the larger area:  60/96 =  5/8 </SPAN>\n" );
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