document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=937336>Question 937336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maria and Zoe are taking Biology 101 but are in different classes. Maria’s class has an average of 78% with a standard deviation of 5% on the midterm while Zoe’s class has an average of 83% with a standard deviation of 12%. Assume that scores in both classes follow a normal distribution. Now suppose that Maria scored an 84 on the midterm exam and Zoe scored an 89. <BR>\n" );
document.write( "Who did better relative to their class?\r<BR>\n" );
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document.write( "How do I convert raw score to percentage when I do not know the total number of test questions.  how do I solve this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #570920 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=570920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> assume 100 point tests<BR>\n" );
document.write( "Maria: p(x = .84) = p(z < .06/.05) = normalcdf(-100,1.2) **** did better<BR>\n" );
document.write( "Zoe: p(x = .89) = p(z < .06/.12) = normalcdf(-100, .5)<BR>\n" );
document.write( "For the normal distribution: Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.  <BR>\n" );
document.write( "area to the left of z = 1.2 > area to the left of z = .5<BR>\n" );
document.write( "Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50%  to the right<BR>\n" );
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