document.write( "Question 937337: The width of a rectangle is 3in shorter than the length. The perimeter is 42in. Find the measurement of each side. \n" ); document.write( "
Algebra.Com's Answer #570919 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( " .\r
\n" ); document.write( "\n" ); document.write( " 2L + 2w = 42in
\n" ); document.write( "L + w = 21in
\n" ); document.write( "L + (L-3in) = 21in
\n" ); document.write( "2L = 24in
\n" ); document.write( "L = 12in and w = 9in \"12-3\"
\n" ); document.write( "and...checking
\n" ); document.write( "L + w = 21in \n" ); document.write( "
\n" );