document.write( "Question 937471: pls help me..!.
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\n" ); document.write( " Express log(ab) + log(sub 100)(a) in terms of u and v if u = log(a^2) and v = log(1/b) .\r
\n" ); document.write( "\n" ); document.write( "pls pls. answer...
\n" ); document.write( "thank you..!
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Algebra.Com's Answer #570879 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Express log(ab) + log(sub 100)(a) in terms of u and v if u = log(a^2) and v = log(1/b)
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\n" ); document.write( "If you mean logs base 10 and
\n" ); document.write( "\"log%28ab%29+%2B+log%28100%2Ca%29\"
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\n" ); document.write( "u = log(a^2) --> u = 2log(a)
\n" ); document.write( "log(a) = u/2
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\n" ); document.write( "v = log(1/b) --> v = log(1) - log(b) = 0 - log(b)
\n" ); document.write( "log(b) = -v
\n" ); document.write( "--------
\n" ); document.write( "\"log%28100%2Ca%29+=+log%28a%29%2F2+=+%281%2F2%29log%28a%29\"
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\n" ); document.write( "log(ab) = log(a) + log(b) = u/2 - v
\n" ); document.write( "=================
\n" ); document.write( "\"log%28ab%29+%2B+log%28100%2Ca%29+=+u%2F2+-+v+-+u%2F4\"
\n" ); document.write( "= \"u%2F4+-+v+\"
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