document.write( "Question 937491: Mary's age is 2/3 that of Peter's. Two years ago Mary's age was 1/2 of what Peter's age will be in 5 years' time. How old is Peter now
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Algebra.Com's Answer #570864 by TimothyLamb(4379)\"\" \"About 
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x = mary age now
\n" ); document.write( "y = peter age now
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\n" ); document.write( "x = (2/3)y
\n" ); document.write( "x - 2 = (1/2)(y + 5)
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\n" ); document.write( "x - 0.666666666y = 0
\n" ); document.write( "x - 2 = (1/2)y + 5/2
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\n" ); document.write( "x - 0.666666666y = 0
\n" ); document.write( "x - (1/2)y = 5/2 + 2
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\n" ); document.write( "x - 0.666666666y = 0
\n" ); document.write( "x - 0.5y = 4.5
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\n" ); document.write( "put the system of linear equations into standard form
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\n" ); document.write( "x - 0.666666666y = 0
\n" ); document.write( "x - 0.5y = 4.5
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\n" ); document.write( "copy and paste the above standard form linear equations in to this solver:
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\n" ); document.write( "solution:
\n" ); document.write( "x = mary age now = 18
\n" ); document.write( "y = peter age now = 27
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