document.write( "Question 937473: The area of a rectangle gets reduced by 8 sq. metre, if its length is reduced by 5 metre and breadth is increased by 3 metre. If we increase the length by 3 metre and breadth by 2 metre, the area is increased by 74 sq. metre. Find the length and breadth of the rectangle.? \n" ); document.write( "
Algebra.Com's Answer #570824 by lwsshak3(11628)\"\" \"About 
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The area of a rectangle gets reduced by 8 sq. metre, if its length is reduced by 5 metre and breadth is increased by 3 metre. If we increase the length by 3 metre and breadth by 2 metre, the area is increased by 74 sq. metre. Find the length and breadth of the rectangle.?
\n" ); document.write( "***
\n" ); document.write( "let x=length of rectangle
\n" ); document.write( "let y=breadth of rectangle
\n" ); document.write( "original area=xy
\n" ); document.write( "xy-(x-5)(y+3)=8
\n" ); document.write( "(x+3)(y+2)-xy=74
\n" ); document.write( "..
\n" ); document.write( " xy-(xy-5y+3x-15)=8
\n" ); document.write( "-xy+(xy+3y+2x+6)=74
\n" ); document.write( "..
\n" ); document.write( " xy-xy+5y-3x+15=8
\n" ); document.write( "-xy+xy+3y+2x+6=74
\n" ); document.write( "..
\n" ); document.write( "5y-3x+15=8
\n" ); document.write( "3y+2x+6=74
\n" ); document.write( "..
\n" ); document.write( "10y-6x+30=16
\n" ); document.write( " 9y+6x+18=222
\n" ); document.write( "add
\n" ); document.write( "19y+48=238
\n" ); document.write( "19y=190
\n" ); document.write( "y=10
\n" ); document.write( "2x=74-6-3y=38
\n" ); document.write( "x=19
\n" ); document.write( "length of rectangle=19 metres
\n" ); document.write( "breadth of rectangle=10 meters \n" ); document.write( "
\n" );