document.write( "Question 937360: Write an equation for the circle in standard form, the state the center and radius. X^2+y^2+12x=6y
\n" ); document.write( "When I answered this question I got (x+6)^2+(y-3)^2=2,025, but I am not sure I got the radius right. Can you explain to me how you get the correct radius? Thank you!
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Algebra.Com's Answer #570765 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Adjust so all variable terms are on one side or the other side.
\n" ); document.write( "Complete The Square for the x and the y.
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\n" ); document.write( "\n" ); document.write( "\"X%5E2%2By%5E2%2B12x=6y\", ?
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2%2B12x=6y\"
\n" ); document.write( "\"x%5E2%2B12x%2By%5E2-6y=0\"
\n" ); document.write( "\"%28x%5E2%2B12x%29%2B%28y%5E2-6y%29=0\"
\n" ); document.write( "\"%28x%5E2%2B12x%2B36%29%2B%28y%5E2-6y%2B9%29=36%2B9\"
\n" ); document.write( "\"highlight%28%28x%2B6%29%5E2%2B%28y-3%29%5E2=45%29\"
\n" ); document.write( "or alternatively equivalent to
\n" ); document.write( "\"highlight%28%28x%2B6%29%5E2%2B%28y-3%29%5E2=%283sqrt%285%29%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "The radius is \"3%2Asqrt%285%29\"
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