document.write( "Question 937255: Solve the following for 0 < x < 2pi\r
\n" ); document.write( "\n" ); document.write( "(sin x + cos x)^2 = 1
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Algebra.Com's Answer #570715 by Alan3354(69443)\"\" \"About 
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Solve the following for 0 < x < 2pi\r
\n" ); document.write( "\n" ); document.write( "(sin x + cos x)^2 = 1
\n" ); document.write( "sin(x) + cos(x) = 1
\n" ); document.write( "By inspection, x = pi/2
\n" ); document.write( "------
\n" ); document.write( "sin(x) + cos(x) = -1
\n" ); document.write( "x = pi
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