document.write( "Question 937255: Solve the following for 0 < x < 2pi\r
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document.write( "(sin x + cos x)^2 = 1 \n" );
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Algebra.Com's Answer #570715 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Solve the following for 0 < x < 2pi\r \n" ); document.write( "\n" ); document.write( "(sin x + cos x)^2 = 1 \n" ); document.write( "sin(x) + cos(x) = 1 \n" ); document.write( "By inspection, x = pi/2 \n" ); document.write( "------ \n" ); document.write( "sin(x) + cos(x) = -1 \n" ); document.write( "x = pi \n" ); document.write( " |