document.write( "Question 937247: A woman has $5,000 invested at 8% annual interest. At what rate must she invest an additional $10,000 so that her annual income from both investments is 9% of her total investment? \n" ); document.write( "

Algebra.Com's Answer #570686 by TimothyLamb(4379) $\"\"$ $\"About$

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x = rate at which 10000 is invested
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\n" ); document.write( "5000*0.08 + 10000x = 15000*0.09
\n" ); document.write( "10000x = 15000*0.09 - 5000*0.08
\n" ); document.write( "x = (15000*0.09 - 5000*0.08)/10000
\n" ); document.write( "x = 0.095
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\n" ); document.write( "answer:
\n" ); document.write( "invest the additional %10,000 at 9.5%
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