document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=937211>Question 937211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the ages of a woman and her daughter is 40. In 4 years time the ratio of their ages will be 7:2. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #570682 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=570682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=current age of woman<BR>\n" );
document.write( "40-x=current age of daughter<BR>\n" );
document.write( "(x+4)/(44-x)=(7/2)<BR>\n" );
document.write( "2(x+4)=7(44-x)<BR>\n" );
document.write( "2x+8=308-7x<BR>\n" );
document.write( "9x=300<BR>\n" );
document.write( "x=33 1/3 years old-----woman's age<BR>\n" );
document.write( "40-x=6 2/3 years old------daughter's age<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "(37 1/3)/(10 2/3)=112/32=7/2<BR>\n" );
document.write( "Does this help?-----ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );