document.write( "Question 79502: solve the equation ln(x+5)-ln(3)=ln(x-3)\r
\n" ); document.write( "\n" ); document.write( "a. 2.5
\n" ); document.write( "b. 4.5
\n" ); document.write( "c. 5
\n" ); document.write( "d. 7 \n" ); document.write( "

Algebra.Com's Answer #57064 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"ln%28x%2B5%29-ln%283%29=ln%28x-3%29\"$
\n" ); document.write( "Use the rule $\"log%28a%2Fb%29+=+log%28a%29+-+log%28b%29\"$ (use it backwards)
\n" ); document.write( " $\"ln%28%28x%2B5%29%2F3%29+=+ln%28x-3%29\"$
\n" ); document.write( "If the natural logs are equal, then the quantities themselves have to
\n" ); document.write( "be equal
\n" ); document.write( " $\"%28x%2B5%29%2F3+=+x-3\"$
\n" ); document.write( " $\"x%2B5+=+3%2A%28x-3%29\"$
\n" ); document.write( " $\"x%2B5+=+3x+-9\"$
\n" ); document.write( " $\"2x+=+14\"$
\n" ); document.write( " $\"x+=+7\"$ answer
\n" ); document.write( "now check answer
\n" ); document.write( " $\"ln%28x%2B5%29-ln%283%29=ln%28x-3%29\"$
\n" ); document.write( " $\"ln%287%2B5%29-ln%283%29=ln%287-3%29\"$
\n" ); document.write( " $\"ln%2812%29+-+ln%283%29+=+ln%284%29\"$
\n" ); document.write( " $\"ln%2812%2F3%29+=+ln%284%29\"$
\n" ); document.write( " $\"ln%284%29+=+ln%284%29\"$
\n" ); document.write( "OK \n" ); document.write( "

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