document.write( "Question 937191: Pls could you help me with this
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document.write( "Marks 10-19 20-29 30-39 40-49 50-59 60-69 70-79 80-89 90-99
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document.write( "Frequency 1 3 7 20 30 22 10 5 2
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document.write( "Using 54.5 as an assumed mean calculate the mean mark and standard deviation of the distribution \n" );
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Algebra.Com's Answer #570626 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! So you need only the standard deviation ?\r \n" ); document.write( "\n" ); document.write( "You can contact me at: \n" ); document.write( "mthman@gmail.com \n" ); document.write( "Thanks \n" ); document.write( " \n" ); document.write( " |