document.write( "Question 79507: An object is shot straight up into the air from ground level with initial speed of 24 ft/sec. The height of the object (in feet) is given by the equation h=-16tsquared+24t, where t is the time in seconds after launch. Find the time(s) when the object is at ground level. \n" ); document.write( "
Algebra.Com's Answer #57061 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An object is shot straight up into the air from ground level with initial speed of 24 ft/sec. The height of the object (in feet) is given by the equation h=-16tsquared+24t, where t is the time in seconds after launch. Find the time(s) when the object is at ground level. \n" ); document.write( "--------- \n" ); document.write( "At ground level the height is zero. \n" ); document.write( "To get the time let h=0 and solve for t: \n" ); document.write( "-16t^2+24t=0 \n" ); document.write( "-8(2t^2-3t)=0 \n" ); document.write( "2t^2-3t=0 \n" ); document.write( "t(2t-3)=0 \n" ); document.write( "t=0 or t=3/2 \n" ); document.write( "This means the object was on the ground to start with (t=0) \n" ); document.write( "and will be on the ground again in 1.5 seconds (t=3/2) \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |