document.write( "Question 79507: An object is shot straight up into the air from ground level with initial speed of 24 ft/sec. The height of the object (in feet) is given by the equation h=-16tsquared+24t, where t is the time in seconds after launch. Find the time(s) when the object is at ground level. \n" ); document.write( "
Algebra.Com's Answer #57061 by stanbon(75887)\"\" \"About 
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An object is shot straight up into the air from ground level with initial speed of 24 ft/sec. The height of the object (in feet) is given by the equation h=-16tsquared+24t, where t is the time in seconds after launch. Find the time(s) when the object is at ground level.
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\n" ); document.write( "At ground level the height is zero.
\n" ); document.write( "To get the time let h=0 and solve for t:
\n" ); document.write( "-16t^2+24t=0
\n" ); document.write( "-8(2t^2-3t)=0
\n" ); document.write( "2t^2-3t=0
\n" ); document.write( "t(2t-3)=0
\n" ); document.write( "t=0 or t=3/2
\n" ); document.write( "This means the object was on the ground to start with (t=0)
\n" ); document.write( "and will be on the ground again in 1.5 seconds (t=3/2)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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