document.write( "Question 937158: The perimeter of a rectangle is 38 cm and its area is 60 cm2. Let x be the width of the rectangle. Find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #570577 by dkppathak(439) $\"\"$ $\"About$

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The perimeter of a rectangle is 38 cm and its area is 60 cm2. Let x be the width of the rectangle. Find the dimensions of the rectangle.
\n" ); document.write( "solution let length is l and breath is b
\n" ); document.write( "P =2(l+b)
\n" ); document.write( "38=2(l+b) l+b =19 (!) or l=19-b
\n" ); document.write( " area lb=60 (2) by substituting the value of l in (2)
\n" ); document.write( "(19-b)b=60
\n" ); document.write( "19b-b^2=60
\n" ); document.write( "b^2 -19b +60 =0
\n" ); document.write( "b^2-15b-4b+60 =0
\n" ); document.write( "(b-4)(b-15) =0
\n" ); document.write( "so b=4 or b=15 and l=4 or l=15
\n" ); document.write( "so dimensions are 4 and 15 cm \n" ); document.write( "

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