document.write( "Question 79503: solve the equation \"4%5E%282x%2B1%29=2%5E%283x%2B6%29\"
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Algebra.Com's Answer #57051 by Edwin McCravy(20060)\"\" \"About 
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document.write( "solve the equation \"4%5E%282x%2B1%29=2%5E%283x%2B6%29\"\r\n" );
document.write( "a. -5\r\n" );
document.write( "b. 2\r\n" );
document.write( "c. 4\r\n" );
document.write( "d. 5\r\n" );
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document.write( "42x+1 = 23x+6\r\n" );
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document.write( "Write 4 as 22\r\n" );
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document.write( "(22)2x+1 = 23x+6\r\n" );
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document.write( "Remove the parentheses on the left by \r\n" );
document.write( "multiplying the exponents:\r\n" );
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document.write( "24x+2 = 23x+6\r\n" );
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document.write( "Set the powers of 2 equal on both sides:\r\n" );
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document.write( "4x + 2 = 3x + 6\r\n" );
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document.write( "     x = 4\r\n" );
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document.write( "Edwin

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