document.write( "Question 10814: The sum of the ages of Ira and Sofia is 26. The difference between 4 times Sofia's age and twice Ira's age is 8. \n" ); document.write( "

Algebra.Com's Answer #5705 by longjonsilver(2297) $\"\"$ $\"About$

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let ages be x and y\r
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\n" ); document.write( "\n" ); document.write( "we then have
\n" ); document.write( "x+y = 26 --eqn1
\n" ); document.write( "and
\n" ); document.write( "4x-2y = 8 --eqn2\r
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\n" ); document.write( "\n" ); document.write( "eqn1, scaled up, is: 4x+4y=104\r
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\n" ); document.write( "\n" ); document.write( "So, we have the following:
\n" ); document.write( "4x+4y=104
\n" ); document.write( "4x-2y = 8\r
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\n" ); document.write( "\n" ); document.write( "Now subtract them, to give 6y = 96\r
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\n" ); document.write( "\n" ); document.write( "--> y = 96/6
\n" ); document.write( "so y =16\r
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\n" ); document.write( "\n" ); document.write( "from eqn1, x+y = 26, so x+16 = 26 --> x = 10\r
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\n" ); document.write( "\n" ); document.write( "check in eqn2:
\n" ); document.write( "4x-2y
\n" ); document.write( "4*10 - 2*16
\n" ); document.write( "40 - 32
\n" ); document.write( "8.. correct\r
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\n" ); document.write( "\n" ); document.write( "jon.
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