document.write( "Question 937033: given that y^2+10y+k is a perfect square trinomial, find the value of k. \n" ); document.write( "
Algebra.Com's Answer #570478 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " \"y%5E2%2B10y%2Bk\" is a perfect square trinomial, \r
\n" ); document.write( "\n" ); document.write( "to find the value of \"k\" use \"10y\" and recall the rule \"%28a%2Bb%29%5E2=a%5E2%2B2ab%2Bb%5E2\"; so,in \"10y\" we know that \"b=y\" and \"2a=10\"=>\"a=5%29%0D%0A%0D%0Ausing+that+we+have+%0D%0A+%7B%7B%7B%28y%5E2%2B10y%2B_%29-_%2Bk\" \r
\n" ); document.write( "\n" ); document.write( "\"%28y%5E2%2B10y%2B5%5E2%29-25%2Bk\" \r
\n" ); document.write( "\n" ); document.write( "\"%28y%2B5%29%5E2-25%2Bk\" ...=> to have a perfect square trinomial \"k\" must be \"25\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y%2B5%29%5E2-25%2B25\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y%2B5%29%5E2\"\r
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