document.write( "Question 79469: x=-4y+4
\n" ); document.write( "5x-3y=-3 solve the system by the substitution method \n" ); document.write( "
Algebra.Com's Answer #57047 by sprolden(40)\"\" \"About 
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x=-4y+4 solve the system by the substitution method
\n" ); document.write( "5x-3y=-3\r
\n" ); document.write( "\n" ); document.write( "1- Substitute -4y+4 for x in the bottom equation.
\n" ); document.write( " 5(-4y+4)-3y=-3\r
\n" ); document.write( "\n" ); document.write( "2- Multiply 5 times all terms in parenthesis.
\n" ); document.write( " -20y+20-3y=-3\r
\n" ); document.write( "\n" ); document.write( "3- Combine like terms.
\n" ); document.write( " -20y-3y+20=-3
\n" ); document.write( " -23y+20=-3\r
\n" ); document.write( "\n" ); document.write( "4- Subtract 20 from each side.
\n" ); document.write( " -23y=-23
\n" ); document.write( " y=1\r
\n" ); document.write( "\n" ); document.write( "5- Substitute 1 into either of the original equations. I'm going to use the first equation.
\n" ); document.write( "x=-4(1)+4
\n" ); document.write( "x=-4+4
\n" ); document.write( "x=0\r
\n" ); document.write( "\n" ); document.write( "6- The solutions are x=0 and y=1.
\n" ); document.write( " CHECK: 0=-4(1)+4 so 0=0\r
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