document.write( "Question 937012: If x is an integer and 2 < x < 7, how many different triangle are there with sides of lengths 2,7 and x?\r
\n" ); document.write( "\n" ); document.write( "This is a multiple choice question with the following answers
\n" ); document.write( "One, Two, Three, Four and Five.\r
\n" ); document.write( "\n" ); document.write( "The answer given was One.\r
\n" ); document.write( "\n" ); document.write( "But the way i understood is x could be of any value of the following 3, 4, 5 and 6. So I selected FOUR. Can you please help me on how the answer is One?
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Algebra.Com's Answer #570462 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"2%3Cx%3C+7\"\r
\n" ); document.write( "\n" ); document.write( "Now, a triangle \"must\" be such that the \"sum\" of \"any\"\"+two\" sides \"must\" be \"greater\" than the \"third\" side.\r
\n" ); document.write( "\n" ); document.write( "So, immediately, we are down to \"3\", \"4\", \"5\", \"6\" under given conditions.\r
\n" ); document.write( "\n" ); document.write( "If \"x+=+3\" then \"2%2B3+%3C+7\" --- not a triangle!
\n" ); document.write( "if \"x+=+4\" then \"2+%2B+4+%3C+7\" -- not a triangle
\n" ); document.write( "if \"x+=+5\" then \"2+%2B+5+=+7\" -- not a triangle
\n" ); document.write( "if x = 6 then \"2%2B+6+%3E+7\" -- \"triangle\"
\n" ); document.write( "so, \"1\" value of \"x\" works; so, answer is \"one\"\r
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